Chillers are extremely energy intensive to operate in the entire HVAC system of a building and that also means these are very expensive to run so, it is important to understand how efficient your chiller is operating.

We're going to be
looking at how to calculate the chiller cooling capacity, and how much cooling
can the chiller produce at any given time during its operation. Now there's going
to be a few things we'll need to know in order to perform this calculation.

So let's imagine we've got our chiller here. We've got the return water that is coming from around the building that will return to water coming in the evaporator where it cools down and then leaves again and goes off through the building.

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Before doing this calculation we need to know some important parameters like

**Q** = Heat Transfer Kw

**T _{in }**= Water Temperature In Evaporator

**T _{out}** = Water Temperature Out Evaporator

**V̇** = Volume Flow Rate

**ρ** = Density of Water

**C _{p}** = Specific Heat Capacity

The values of density
of water and specific heat capacity of water will be taken at average
temperature = **(T**_{in+}
T_{out})/**2**

To find the
values you can simply look them up in your engineering tables in books, or you
go here to find the values.

We're going to
assume that

Volume Flow Rate **V̇**** = ****0.0995 m ^{3}/s**

Water Temperature In **T**_{in }= **12 ˚C**

Water Temperature Out **T**_{out} = **6 ˚C**

Average Temperature = **(T**_{in+} T_{out})/**2 = (12+6)/2 = 9 ˚C**

For density and specific
heat capacity at average go to the above link and put to values of working
pressure and average temperature i.e.

Pressure **P = 101.325 kPa**

Average Temperature = **9˚C**

You will get

Density of Water **ρ = ****999.78 kg/m ^{3}**

Specific Heat Capacity **C**_{p} = **4.19 kj/kg.K**

Now Formula for the for the heat transfer is

**Q = ( V̇ x
ρ ) x C _{p} x (T_{in} - T_{out }**

**)**

Where V̇ x
ρ = Mass Flow Rate

Now put the values in the above equation

**Q = (0.0995 ****m ^{3}/s
x 999.78 kg/m^{3}) x 4.19 kj/kg.K x ((12˚C +273.15K) – (6˚C + 273.16K))**

Note: **273.16K** is
added in the temperature to convert Celsius into Kelvin.

Simplifying above
equation:

**Q = 99.48 kg/s x
4.19 kj/kg.K x (285.15K – 279.15K)**

**Q = 99.48 kg/s x
4.19 kj/kg.K x 6K**

**Q = 2500 kW**
(Refrigeration effect)

To convert it
into Ton of Refrigeration divide it by **3.517**

**Q = 2500 kW /
3.517**

**Q = 711 TR**
Refrigeration Tons

To convert it
into BTU/h multiply above value with **3412.142**

**Q = 2500 kW x
3412.145**

**Q = 853357 BTU/h**

So that is how you calculate your cooling capacity of the chiller and you can apply this any time during its operation, whether it's a part load or a full load, it will be calculated like this. If you have any comments, leave them in the comment section down below.

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